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The ratio in which the line 3x+4y+2=0 di...

The ratio in which the line 3x+4y+2=0 divides the distance between 3x+4y+5=0 and 3x+4y-5=0 is?

Text Solution

Verified by Experts

We know,
Distance=`|(C_2-C_2)/sqrt(A^2+B^2)|`
From 1 and 2
m=`|(5-2)/sqrt(3^2+4^2)|=3/5`
n=`|(2+5)/sqrt(3^2+4^2)|=7/5`
Ration of m and n
m:n=`(3/5)/(7/5)=3/7`.
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