Home
Class 12
PHYSICS
Photons of frequencies 2.2xx10^(15) Hz a...

Photons of frequencies `2.2xx10^(15) Hz` and `4.6xx10^(15) Hz` are incident on a metal surface. The corresponding stopping potentials were found to be `6.6V` and `16.5V` respectively. Given `e=1.6xx10^(-19) c`, the value of universal planck's constant is

Promotional Banner

Similar Questions

Explore conceptually related problems

A photon of frequency 1.5xx10^(15) Hz is incident on a metal surface of work function 1.672 eV. Calculate the stopping potential.

The threshold frequency for a certain metal for photoelectric effect is 1.7x10^(15)Hz . When light of frequency 2.2xx10^(15)Hz is incident on the metal surface, the kinetic energy of the emitted photoelectrons is 3.3xx10^(-19)J . What is the value of the Planck's constant ?

A photon of frequency 5 xx 10^(14)Hz is incident on the surface of a metal. What is the energy of the incident photon in eV?

Energy of an quanta of frequency 10^(15) Hz and h = 6.6 xx 10^(-34) J - sec will be

In an experiment on photoelectric effect, the slope of the cut off voltage versus frequency of incident light is found to be 4.12xx10^(-15)Vs . Given e=1.6xx10^(-19)C , estimate the value of Planck's constant.

In an experiment on photoelectric effect, the slope of the cut off voltage versus frequency of incident light is found to be 4.12xx10^(-15)Vs . Given e=1.6xx10^(-19)C , estimate the value of Planck's constant.

The threshold frequency for a certain metal for photoelectric effect is 1.7 xx 10^15 Hz .When light of frequency 2.2 xx 10^15 Hz is incident on the metal surface, the kinetic energy of the emitted. photoelectrons is 3.3 xx 10^-19 J .Calculate Planck's constant.

If light of frequency 8.2 xx 10^(14) Hz is incident on the metal , cut-off voltage for photoelectric emission is 2.03 V. Find the threshold frequency . Given h = 6.63 xx 10^(-34) Js , e = 1.6 xx 10^(-19) C .

If high waves of frequency 8.8 xx 10^(14) Hz is incident on a metal surface of thresold frequency 4 xx 10^(14) Hz, then determine the value of stopping potential (cut-off Potential) (Given h=6.6 xx 10^(-34) Js and e = 1.6 xx 10^(-19)C)

Frequency of a wave is 6 xx 10^(15) Hz. The wave is