Home
Class 11
MATHS
[" 8.The centre of the circle "r^(2)=2-4...

[" 8.The centre of the circle "r^(2)=2-4r cos theta+6r sin theta" is "],[[" (a) "(2,3)," (b) "(-2,3)],[" (c) "(-2,-3)," (d) "(2,-3)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The radius of the circle r = 12 cos theta + 5 sin theta is

The radius of the circle r^(2)-2sqrt(2r) (cos theta + sin theta)-5=0 , is

The radius of the circle r^(2)-2sqrt(2r) (cos theta + sin theta)-5=0 , is

The radius of the circle r = sqrt(3) sin theta + cos theta is

The centre of the circle r^(2) - 4r (cos theta + sin theta) - 4 = 0 in cartesian coordinates is

The centre, radius of the circle r^(2) - 8 r cos (theta - (pi)/(3) ) + 12 =0 is

If x=r cos theta,y=r sin theta, show that

If x=r cos theta, y=r sin theta Prove that x^(2)+y^(2)=r^(2)

The angle of intersection of the curves r=sin theta+cos theta and r=2sin theta is 1. (pi)/(6) 2. (pi)/(3) 3. (pi)/(4) 4. (pi)/(2)