x!=a(cos theta+theta sin theta),quad y=a(sin theta-theta cos theta)

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

Find (dy)/(dx), when x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta)

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find (dy)/(dx) . x= a (cos theta+ theta sin theta), y= a (sin theta-theta cos theta) .

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find (dy)/(dx) . x= a (cos theta+ theta sin theta), y= a (sin theta-theta cos theta) .

Show that the normal at any point theta to the curve x=a(cos theta+ theta sin theta), y=a( sin theta- theta cos theta) is at a constant distance from the origin.

If x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta) and theta increases at uniform rate omega . The velocity of particle is

Consider the curve x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta). What is (dy)/(dx) equal to? What is (d^(2)y)/(dx^(2)) equal to?