x^(2)-6x+4=0

Two circle x^(2)+y^(2)=6 and x^(2)+y^(2)-6x+8=0 are given.Then the equation of the circle through their points of intersection and the point (1,1) is x^(2)+y^(2)-6x+4=0x^(2)+y^(2)-3x+1=0x^(2)+y^(2)-4y+2=0 none of these

the equation whose roots are multiplied by -3 of those of 9x^(2)-6x^(2)+5x-4=0 is

x^(4)-4x^(3)+6x^(2)-4x+1=0 The roots of the equation are

The maximum possible number of real roots of the equation x^(5)-6x^(2)-4x+5=0 is

Find the maximum possible number of real roots of the equation. x^(5)-6x^(2)-4x+5=0 .

The focus of the conic x ^(2) -6x + 4y +1=0 is

The focus of the conic x^(2)-6x+4y+1=0 is

The vertex of the parabola x^(2)-6x+4y+1=0 is

The fouce of the parabola x^(2)-6x+4y+1=0 is