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100 ml of a sample of water requires 0.9...

100 ml of a sample of water requires 0.98mg of `K_(2)(M.W.= 294 )` in presence of the `H_(2)SO_(4)` for the oxidation of dissolved organic matter in it. The COD of the water sample is

A

78.4 ppm

B

1.6 ppm

C

3.2 ppm

D

6.4 ppm

Text Solution

Verified by Experts

The correct Answer is:
B
49 g of `K_(2)Cr_(2)O_(7) -= 8 g of O_2`
`C.O.D= (Wt. of O_2)/("Wt. of sample of water") xx 10^6`
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