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Normal water is mainly protium oxide, H(...

Normal water is mainly protium oxide, `H_(2)O` However, if protium atoms in normal water molecule are replaced completely by deuterium atoms, the resulting water is called heavy water.
The ionization constant of protum water `(H_(2)O hArr H^(+)+OH) is 1xx10^(-14)` and that in heavy water `(D_(2)O hArr OD^(-)) is 3xx10^(-15) is 3xx10^(-15) H_(2)O` dissociates about

A

three times as much as `D_(2)O` does

B

thirty times as much as `D_(2)O` does

C

`0.3` times as much as `D_(2)O` does

D

300 times as much as `D_(2)O` does

Text Solution

Verified by Experts

The correct Answer is:
A
`((K_(w))_(H_(2)O))/((K_(w))_(D_(2)O))=(1xx10^(-14))/(3xx10^(-15))=(10)/(36)=3.333`
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