Pure `H_(2)O_(2)` is not very stable and decomposes in the presence of light or on standing or heating
`overset((-1))(H_(2)O_(2l))+overset((2-)) (H_(2)O_((l)))+overset((0))(O_(2(g)))`
The oxidation state of oxygen in `H_(2)O_(2)` is 1 it is oxidistion state of zero in `O_(2)` and is reduced to an oxidation state of -2 in `H_(2)O`. Thus, this decomposition is an example of auto oxidation reduction reaction or disproportionation reaction.
30-volume, hydrogen peroxide means

Options

A. 30 % of `H_(2)O_(2)` by volume
B. 30 g of `H_(2)O_(2)` solution contains 1g of `H_(2)O`
C. `1 cm^(3)` of solution liberates `30 Cm^(-3)` dioxygen gas at STP
D. `30 cm^(3)` of the solution contains one mole of `H_(2)O_(2)`

Answer

C

Explanation

30- Volume hydrogen peroxide means `1 cm^(3)` of solutio liberats `30cm^(-2)` of dioxygen gas at STP.