Last molecule of H(2) O is removed from ...

Last molecule of `H_(2) O` is removed from `H_(2)O_(2)` by

crystallisation

evaporation

distillation under reduced pressure

electrolysis

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The correct Answer is:

`H_(2)O_(2)` solution is concentrated in 3 steps. In the last step its is coccentrated by crystallisaiton

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H_(2)O_(2) reduces

H_(2)O_(2) acts both as oxidant and reductant. H_(2)O and O_(2) are products when H_(2)O_(2) acts as oxidant and reductant respectively. The strength of H_(2)O_(2) is expressed in terms of molarity, normality, % strength and volume strength. H_(2)O_(2) decomposes as H_(2)O_(2)rarrH_(2)+1//2O_(2)(g) i.e., one mole O_(2) is released from 2 mole H_(2)O_(2) .x. .volume. strength of H_(2)O_(2) means 1 volume (mL or litre) of H_(2)O_(2) sample released x volume (mL or litre) O_(2) gas at NTP on its decomposition. Hence molarity = x//11.2 moles per litre, i.e., normality of H_(2)O_(2)=x//5.6 Thus volume strength, i.e., x=5.6xx Normality. Weigth of H_(2)O_(2) (in gm) present in 100 mL H_(2)O_(2) solution is called percentage strength of H_(2)O_(2) How much volume of H_(2)O_(2) solution of 22.4 .vol. strength is required to oxidise 6.3 gm oxalic acid

The structure of H_(2)O_(2) is

H_(2) gas is liberated when H_(2)O_(2) reacts with

20 volume. of H_(2)O_(2) is equal to

Compare the structures of H_(2)O and H_(2)O_(2)

(A) Thermal stability of 16 ^(th) group hydrides decreases from H _(2) O to H_(2) PO (R ) From H _(2)O to H_(2)PO bond dissociation energy increases.

Which is not a property of H_(2)O_(2)

AAKASH SERIES-HYDROGEN AND ITS COMPOUNDS-PRACTICE SHEET (EXERCISE-I) (LEVEL-II (ADVANCED) Straight Objective Type Questions )

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