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100mL of om at STP was passed through 10...

100mL of om at STP was passed through 100 ml of 10 volume `H_(2)O_(2)`solution. What is the volume strength of `H_(2)O_(2)` after the reaction?

A

`9.5`

B

`9.0`

C

`4.75`

D

`4.5`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)O_(2)+O_(3) to H_(2)+2O_(2)`
initial `M_(H_(2)O_(2))=(10)/(11.2)=(10)/(11.2)M`
number of mols of `O_(2)=(0.1)/(22.4)`
number of moles of `O_(2)=(10)/(11.2)xx0.1`
According to stoichiometric equation on mole of `H_(2)O_(2)` produce 1 mole of `O_(3)` numbeer of mles of `H_(2)O_(3)` consumed
`=(1)/(224)`, remains `=(19)/(224)`
on molarity `=11.2(W//V)%`
`(19)/(224)xx0.1 -----?`
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