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Hydrogen peroxide is ionise as : H(2)O(2...

Hydrogen peroxide is ionise as `: H_(2)O_(2) hArr H^(+)+HO_(2)^(-)`. If `p^(h) of H_(2)O_(2)` is `5.91` at `25^(@)C` the ionic product of `H_(2)O_(2)` is

A

`1.51xx10^(-12)`

B

`1.15xx10^(-12)`

C

`1xx10^(-14)`

D

`1.1xx10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[H^(+)] at 25^(@)C=10^(-5.91)=1.23xx10^(-6)M`
`[H^(+)] at 25^(@)C=10^(-5.91)=1.23xx10^(-6)M`
`K=[H^(+)][HO_(2)^(-)]=[1.23xx10^(-6)]^(2)=1.51xx10^(-2)`
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