The number of hybrid orbitals involved in the formation of `B_(2)H_(6), B_(3)N_(3)H_(6), BCl_(3),H_(3)BO_(3)` are p, q, r & s, then the sum of `(p+q+r+s)` is 8y, then y = ?

Answer

4

Explanation

`B_(2)H_(6)to 8 ["each "B-4sp^(3)]`
`B_(3)N_(3)H_(6)to 18 ["each "B, N-3sp^(2)]B_(3)N_(3)H_(6)rarr 18 ["each "B, N-3sp^(2)]`
`BCl_(3)to 3 ["each "B-3sp^(2)]`
`H_(3)BO_(3)to 3["each "B-3sp^(2)]`
`P+Q+R+S rArr 8+18+3+3=32(8y)`
`therefore y=4`.