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Twenty millilitres of a gaseous hydrocar...

Twenty millilitres of a gaseous hydrocarbon required 400 ml of air for complete combustion. The air contains 20% by volume of oxygen. The volume of gaseous mixture after explosion and cooling was found to be 380 ml.
Formula of the hydrocarbon is

A

`Me - -= - H`

B

`H_(2)C=C=CH_(2)`

C

D

All

Text Solution

Verified by Experts

The correct Answer is:
D
D.U. in `C_(3)H_(4)=((2n_(C )+2)-n_(H))/(2)=2^(@)`
Here, 3 D.U. means, it can have either one `(C-=C)` bond or two (C = C) bonds or cyclic compound with one (C = C) bond. The structures can be :
(I) `Me-C-=CH`
(II) `H_(2)C=CH_(2)`
(III) `Delta`
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