A sample of hard water contains `1 xx 10^(-3)` mole of `CaCl_2` per 10kg of water. Calculate the degree of hardness of water sample

Explanation

Weight of `CaCl_2` present in 10kg of water
` = 10^(-3) "moles" = 111 xx 10^(-3) g `
Weight of `CaCl_2` present in `10^6` g of water = `(111 xx 10^(-3) xx 10^6)/(10^4) = 11.1g`
111g of `CaCl_2 = 100g ` of `CaCO_3`
11.1 g of `CaCl_2 = 10g `of `CaCO_3`
The degree of hardness of given sample = 10 ppm