Home
Class 11
CHEMISTRY
E^(0) values for Cl(2), Cl^(-), I(2)^(-)...

`E^(0)` values for `Cl_(2), Cl^(-), I_(2)^(-), Ag^(+), Ag, Na^(+), Na, Li^(+), Li`  are respectively `+ 1.36. + 0.53, + 0.79, - 2.71 and - 3.04V`. Correct decreasing order of reducing strength of `I^(-), Ag, Na and Li` is

A

`Cl^(-) gt I^(-) gt Ag gt Na gt Li`

B

`Cl^(-) gt Ag gt I^(-) gt Na gt Li`

C

`Li gt Na gt Ag gt I^(-) gt Cl^(-)`

D

`Li gt Na gt I^(-) gt Ag gt Cl^(-)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ALKALI METALS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 2 (SODIUM SALTS)|17 Videos

  • ALKALI METALS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|35 Videos

  • ALKALI METALS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (BIOLOGICAL IMPORTANCE)|3 Videos

  • ALIPHATIC HYDROCARBONS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|24 Videos

  • ALKALINE EARTH METALS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE ADDITIONAL QUESTIONS|15 Videos

Similar Questions

Explore conceptually related problems

E^(@) value of Co^(2+), Co, Al^(3+) , Al , Ag^(+), Ag and Ba^(2+), Ba are respectively 0.28, -1.66, +0.8 and -2.9 V . write the increasing order of the reduction ability of metals and discuss .

The E^(ɵ) for Cl_2//Cl^(-) is + 1.36, for I_2 //I^(-) is + 0.53, for Ag^(+)//Ag is + 0.79, Na^(+)//Na is -2.71 and for Li^(+)//Li is -0.35 . Arrange the following ionic species in decreasing order of reducing strength : I^(-), Ag, Cl^(-), Li, Na

Standard electrode potential (E^(0)) for OCl^(-) // Cl^(-) and Cl^(-)// (1)/(2) Cl_2 are respectively 0.94 V and -1.36 V . The E^(@) value of OCl^(-) //Cl_2 will be

E^(@) Values of the half cells Mg^(2+)//Mg and Cl_(2)//Cl^(-) are respectively -2.36V and +1.36 V. The E^(@) vlaue of the cell Mg//Mg^(2+)// // Cl_(2)//Cl^(-) is

E^(@) values of Ni^(2+) , Ni and Cl_(2), Cl^(-) are respectively -0.25V and +1.37V . Calculate the EMF of the cell Ni, Ni^(2+) (0.01M)//Cl^(-)(0.1M), Cl_(2) , pt. Potential of nickel electrode is given as,

Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V and Zn^(2+) + 2e^(-) rarr Zn, E^(0) = -076 V . Calculate the cell potential for the reaction, 2Ag + Zn^(2+) rarr Zn + 2Ag^(+)