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(IE)1 and (IE)2 of Mg((g)) are 740, 1540...

`(IE)_1` and `(IE)_2` of `Mg_((g))` are 740, 1540 kJ `mol^(-1)` . Calculate percentage of `Mg_((g))^(+)` and `Mg_((g))^(2+)` if 1 g of `Mg_((s))` absorbs 50.0 kJ of energy.

A

`%Mg^+` = 70% %`Mg^(+2)` = 30%

B

%`Mg^+` =68.35% %`Mg^(+2)` = 31.65%

C

% `Mg^(+)` = 72% %`Mg^(+2)` = 28%

D

%`Mg^+` = 60% % `Mg^(+2)` = 40%

Text Solution

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The correct Answer is:
B
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