A light string fixed at one end to a clamp on ground passes over a fixed pulley and hangs at the other side. It makes an angle of `30^(@)` with the ground. A monkey of mass 5 kg climbs up the rope. The clamp can tolerate a vertical force of 40 N only. The maximum acceleration in upward direction with which the monkey can climb safely is:
(neglect friction and take `g=10m//s^(2))`

A light string fixed at one end to a clamp on ground passes over a fixed pulley and hangs at the other side. It makes anangle of 30^(@) with the ground. A monkey if makes an angle of 30^(@) with the ground. A monkey of mass 5kg climbs up the rope. The clamp can tolerate is vertical force of 40N only. the maximum accelration in upward direction with which the monkey can climb safety is (Neglect friciton and take g=10m//s^(2) )

A light rope fixed at one end of a wooden clamp on the ground passes over a tree branch and hangs on the other side. It makes an angle of 30^0 with the ground. A man weighing (60 kg) wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360 N is applied it. Find the maximum acceleration in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g=10 m/s^2

A light rope fixed at one end of a wooden clamp on the ground passes over a tree branch and hangs on the other side. It makes an angle of 30^0 with the ground. A man weighing (60 kg) wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360 N is applied it. Find the maximum acceleration in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g=10 m/s^2

One end of a light string is fixed to a clamp on the ground and the other end passes over a fixed frictionless pulley as shown in the figure. It makes an angle of 30^(@) with the ground . The clamp can tolerate a vertical force of 40 N . If a monkey of mass 5 kg were to climb up the rope then the maximum acceleration in the upward direction with which it can climb safely is (g=10 ms^(-2))