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If the Pb^(2+) concentration is maintain...

If the `Pb^(2+)` concentration is maintained at 1.0M what is the `[Cu^(2+)]` , when the cell potential drops to zero ?
`E_("cell")^@ = 0.473V, Pb(s) // Pb^(2+) // Cu^(2+) // Cu(s)`

A

`1 xx 10^(-16) M`

B

`1 xx 10^15 M`

C

`1 xx 10^(-14)M`

D

`1 xx 10^14 M`

Text Solution

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The correct Answer is:
A
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