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Adding powdered lead and iron to a solut...

Adding powdered lead and iron to a solution that is 1M in both `Pb^(2+)` and `Fe^(2+)` ions, would results to a reaction in which `(E^@ Fe^(2+)//Fe = -0.44V, E^@Pb^(2+)//Pb = -0.13V)`

A

more amount of Pb and Fe is formed

B

more amount of `Pb^(2+)` and `Fe^(2+)` formed

C

more amount of Pb and `Fe^(2+)` is formed

D

more amount of `Pb^(2+)` and Fe is formed.

Text Solution

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The correct Answer is:
B
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