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When E(Ag^(+) | Ag)^@ = 0.80 volt and E...

When `E_(Ag^(+) | Ag)^@ = 0.80` volt and `E_(Zn^(2+)|Zn)^@ = 0.76` volt, which of the following is correct?

A

`Ag^+` can be reduced by `H_2`

B

Ag can oxidise `H_2` into `H^+` ion

C

`Zn^(+2)` can be reduced by `H_2`

D

Ag can reduce `Zn^(+2)` ion

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The correct Answer is:
A
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Given E_(Ag^(+) // Ag)^(0) = 0.80 V , E_(Mg^(2+) // Mg)^(0) =-2.37 V , E_(Cu^(2+) // Cu)^(0) = 0.34 E_(Hg^(2+) // Hg)^(0) = 0.79 V Which of the following statement is / are correct ?

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The half cell reaction, with its standard reduction potentials are I) Pb^(2+) + 2Ag to 2Ag^(+) + Pb (E^(0) = -0.13V) II) Ag^(+) + e^(-) to Ag(E^(0) = + 0.80 V) Which of the following reactions will occur ?

The emf of the following three galvanic cells are respresented by E_(1), E_(2) and E_(3) respectively. Which of the following is correct? (i) Zn//Zn^(2+) (1M)// //Cu^(2+)(1M)//Cu (ii) Zn//Zn^(2+) (0.1M)// //Cu^(2+)(1M)//Cu (iii) Zn//Zn^(2+)(1M)// //Cu^(2+)(0.1M)//Cu

For I_2 + 2e to 2I^(-) , standard reduction potential = + 0.54 volt. For 2Br^(-) to Br_2 + 2e^(-) . Standard oxidation potential = - 1.09 volt. For Fe to Fe^(2+) + 2e^(-) , standard oxidation potential = + 0.44 volt. Which of the following reaction is non-spontaneous ?

E_(Cu^(2+)|Cu)^@ = +0.337 V, E_(Zn^(2+)| Zn)^@ = - 0.762 V. The EMF of the cell , Zn|Zn^(2+) (0.01M)||Cu^(2+) (0.01M)|Cu is

Ag^(+) + e^(-) rarr Ag, E^(0) = + 0.8 V and Zn^(2+) + 2e^(-) rarr Zn, E^(0) = -076 V . Calculate the cell potential for the reaction, 2Ag + Zn^(2+) rarr Zn + 2Ag^(+)

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