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E^@ of Fe|Fe^(2+) is +0.44V , E^@ of Cu|...

`E^@` of `Fe|Fe^(2+)` is +0.44V , `E^@` of `Cu|Cu^(2+)` is -0.32V. Then in the cell

A

Cu oxidises `Fe^(2+)`ion

B

`Cu^(2+)` oxidises iron

C

Cu reduces `Fe^(2+)` ion

D

`Cu^(2+)` ion reduces Fe

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The correct Answer is:
B
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