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(1-costheta+isintheta)/(1+costheta-isint...

`(1-costheta+isintheta)/(1+costheta-isintheta)`

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The correct Answer is:
`i tan (theta)/(2)`
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Assertion (A) : (Costheta+iSintheta)^(10)+(Costheta-iSintheta)^(10)=2cos10theta Reason (R) : (1+costheta+isintheta)^n+(1+costheta-isintheta)^n= 2^(n+1)cos^n(theta/2)cos((ntheta)/(2))

(costheta+isintheta)^(10)+(costheta-isintheta)^(10)

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =

(1-costheta+isintheta)^(6)

If (1+costheta+isintheta)(1+cos2theta+isin2theta)=x+iy then y =

If (1+costheta-isintheta)(1+cos2theta+isin2theta)=x+iy then x^2+y^2 =

(1+costheta+isintheta)^(n)+(1+costheta-isintheta)^(n)

((costheta+isintheta)^5(cos3theta-isin3theta)^6)/((cos2theta+isin2theta)^3(cos4theta-isin4theta)^5)=

((costheta+isintheta)^(5)(cos3theta-isin3theta)^(6))/((cos2theta+isin2theta)^(3)(cos4theta-isin4theta)^(5))