If ` cos alpha + cos beta + cos gamma = 0 `
` = sin alpha + sin beta + sin gamma ` then show that
`cos ( alpha + beta) + cos ( beta + gamma) + cos ( gamma + alpha) = 0 `

If cos alpha + cos beta + cos gamma =3 , " then " sin alpha + sin beta + sin gamma =

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then show that cos 3 alpha + cos 3 beta + cos 3 gamma = 3 cos ( alpha + beta + gamma)

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then show that sin 3 alpha + sin 3 beta + sin 3 gamma = 3 sin ( alpha + beta + gamma)

If cos(alpha - beta) + cos(beta - gamma)+ cos(gamma-alpha)=-3/2 , then

cos alpha + cos beta + cos gamma + cos ( alpha + beta + gamma ) =

Assertion (A): If A, B, C are the angles of a triangle such that cos A + cos B + Cos C = 0 = sin A + sin B + sin C then cos 3A + cos 3B + cos 3C = -3 Reason (R) : If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + singamma then cos 3 alpha + cos 3 beta + cos 3 gamma = 3 cos (gamma+alpha+beta)

If cos alpha+cos beta+cos gamma=0 & sin alpha +sin beta +sin gamma=0 . Then Prove that sin2alpha+sin2beta+sin2gamma=0

If cos alpha + cos beta + cos gamma = 0 sin alpha + sin beta + sin gamma , Prove that cos^(2) alpha + cos^(2) beta + cos^(2) gamma = 3/2 = sin^(2) alpha + sin^(2) beta + sin^(2) gamma .

cos (alpha + beta + gamma ) + cos (alpha - beta - gamma) + cos ( beta - gamma - alpha ) + cos ( gamma - alpha - beta )=

If cos alpha + cos beta =0 = sin alpha + sin beta " then " cos (alpha - beta )=