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If xn=cos(pi/2^n)+isin(pi/2^n), then x1 ...

If `x_n=cos(pi/2^n)+isin(pi/2^n)`, then x1 x2 x3......infinity

A

`x_1+x_2+…=1`

B

`x_1-x_2+x_3…=0`

C

`x_1x_2x_3…=1`

D

`x_1.x_2.x_3…=-1`

Text Solution

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The correct Answer is:
D
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