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If cos alpha+2cos beta+3cos gamma=sinalp...

If `cos alpha+2cos beta+3cos gamma=sinalpha+2sinbeta+3singamma=0` then `sin 3alpha+8sin3 beta+27sin 3gamma=`

A

`18cos(alpha+beta+gamma)`

B

`18sin(alpha+beta+gamma)`

C

`sin(alpha+beta+gamma)`

D

`cos(alpha+beta+gamma)`

Text Solution

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The correct Answer is:
B
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