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The modulus argument form of 1+iTantheta...

The modulus argument form of 1+iTan`theta` when `theta epsilon (pi/2,pi)` is

A

`SecthetaCIstheta`

B

`-SecthetaCis(pi+theta)`

C

`-SecthetaCis(theta-pi)`

D

none of these

Text Solution

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The correct Answer is:
C
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