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If four squares are chosen at random on a chess board, then the probability that they lie in a diagonal line is

A

`(4sum_(n=4)^(8).^(n)C_(4))/(.^(64)C_(4))`

B

`(2sum_(n=4)^(8).^(n)C_(4))/(.^(64)C_(4))`

C

`(2sum_(n=4)^(7).^(n)C_(4)+.^(8)C_(4))/(.^(64)C_(4))`

D

`(2sum_(n=4)^(7).^(n)C_(4)+2(.^(8)C_(4)))/(.^(64)C_(4))`

Text Solution

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The correct Answer is:
D
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