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One hundred tickets are numbered as 00,0...

One hundred tickets are numbered as 00,01,02,…..,09,10,11,….,99 and one ticket is drawn at random from them. If A is the event of getting 9 as the sum of the numbers on the ticket and B is the event of getting 0 as the product of the numbers on the tickets then `P(AnnB)=`

A

`(1)/(100)`

B

`(2)/(100)`

C

`(10)/(100)`

D

`(19)/(100)`

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The correct Answer is:
B
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