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The equation of the transverse and cojug...

The equation of the transverse and cojugate axes of a hyperbola are respectively `x+ 2y -3=0 ,2x -y+4=0`
and their respectively length are` sqrt 2 and 2//sqrt 3` . The equation of the hyperbola is

A

` (2)/(5) (2x-y+4) ^(2) -(3)/(5) (x+2y-3) ^(2) = 1 `

B

` (2)/(5) (2x- y+3)^(2) -(3)/(5) (x+2y -3)^(2) =1`

C

` 2 ( 2x- y+4) ^(2) -3( x+2y-3) ^(2) =1`

D

` 2(x+2y-3) ^(2) -3(2x- y +4) ^(2) =1`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The equation of the latusrectum of the hyperbola 3y^(2)-4x^(2)=12 are

    A
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    B
    `y=pm sqrt3`
    C
    `y=pm sqrt7`
    D
    `y=pm sqrt5`

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    A
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    ` 2x+-5y =0`
    C
    ` 2x+-6y=0`
    D
    ` 2x+-8y=0`

  • One of the foci of the hyperbola is origin and the corresponding directrix is 3x + 4y + 1=0 .The eccentricity of the hyperbola is sqrt 5 .The equation of the hyperbola is

    A
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    B
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