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AAKASH SERIES-INDEFINITE INTEGRALS -PRACTICE EXERCISE
- Evaluate int x sec^(-1) xdx
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- If f(x), g(x) are primitives of phi (x) then
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- int (1-x^(4))/(1-x)dx=
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- int (x^(4) + x^(2) +1)/(x^(2) + 1) dx =
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- int (x^(6) - 1)/(x^(2) +1) dx =
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- int (x^(8))/(x^(6) + 1) dx =
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- int sin^(2)x sec^(2) x dx=
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- int (tan x - cot x )^(2) dx =
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- int(1)/(1+ cos x) dx on I sub R \\{(2n +1) pi : n in Z}.
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- int (1)/(1 + cos 2 x) dx =
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- int (1)/(cos 2 x + sin^(2) x) dx =
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- If 0 lt x lt (pi)/(2) then int [ 1+ 2 cot x (cot x " cosecx" )]^(1//...
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- Evaluate int ("cos" 2x - cos 2 alpha)/(cos x - cos alpha )
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- If x in ((pi)/(6), (pi)/(3)) " then " int tan^(-1) sqrt((1 - cos 2x)/(...
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- int (sin (x -a))/(sin x) dx =
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- int (sin(x-a))/(cos (x-b))dx=
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- If int (sin 2x + cos 2x) dx = (1)/(sqrt(2)) sin (2x - c) + a then c =
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- int sin^(3) x.cos^(2) x dx =
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- int (sin x cos x)/(1 + cos^(4) x ) dx =
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- int (cos x + x sin x)/(x (x - cos x)) dx=
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- int (1)/((e^(x) - e^(-x))^(2)) dx =
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