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AAKASH SERIES-INDEFINITE INTEGRALS -EXERCISE - I
- int (sin^(6)x)/(cos^(8)x)dx=
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- int (1)/(x^(2)) e^((x - 1)/(x)) dx =
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- int (dx)/((x-1)sqrt(x^(2)-1))=
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- int (x +1)/(x^(2) + 1) dx =
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- int (1)/(x (2 +3 log x )) dx =
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- int (1+log x)/(1+x log x)dx=
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- int (dx)/(x(1+log x)^(3))=
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- int (1-tanx)/(1+tan x)dx=
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- int (1)/(sqrt(x)+x)dx=
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- int (1)/("cosecx" - cot x) dx =
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- Evaluate the integerals. int sqrt(e ^(x) -4) dx on [log (e) 4, oo...
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- If int (e^(x)-1)/(e^(x)+1)dx=f(x)+c, then f(x)=
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- int(x^(e-1)+e^(x-1))/(x^(e)+e^(x))dx=
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- int (e^(x)+e^(-x))/((e^(x)-e^(-x)) log sin hx)dx=
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- int (e^(x))/((1 + e^(2x)) tan^(-1) (e^(x)) ) dx =
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- int sec x "cosec" x dx=
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- If int (4 sec^(2)" x tan x")/(sec^(2) " x + tan"^(2) x)" dx = log " |1...
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- int (1)/(" tan x tan" (60^(@) - x) tan (60^(@) + x) ) dx =
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- int (sin 2x)/(1+ sin^(4)x)dx=
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- int (1)/(sqrt(2 + 3x^(2))) dx =
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