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int xSec^(2) 2x dx =...

`int xSec^(2) 2x ` dx =

A

`(x)/(2) tan2x - (1)/(4)` log | cos2x |+c

B

`(x)/(2) tan2x - (1)/(2)` log | cos2x |+c

C

`(x)/(2) tan2x + (1)/(2)` log | cos2x |+c

D

`(x)/(2) tan2x + (1)/(4)` log | cos2x |+c

Text Solution

Verified by Experts

The correct Answer is:
D
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