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int cos x cos 2x cos 3x dx=...

`int cos x cos 2x cos 3x dx=`

A

`(1)/(4) [ (1)/(6) sin 6x + (1)/(2) sin 2x - (1)/(4) sin 4x + x ] ` + c

B

`(1)/(4) [ (1)/(6) sin 6x - (1)/(2) sin 2x - (1)/(4) sin 4x - x ] ` + c

C

`(1)/(4) [ (1)/(6) sin 6x + (1)/(2) sin 2x + (1)/(4) sin 4x + x ] ` + c

D

`(1)/(6)` sin 6x + c

Text Solution

Verified by Experts

The correct Answer is:
C
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