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AAKASH SERIES-INDEFINITE INTEGRALS -EXERCISE -II
- If int (1)/(x sqrt(1 - x^(3))) " dx = a log" | (sqrt(1- x^(3)) - 1)/(s...
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- int 5^(5^(5^(x)))*5^(5^(x))*5^(x)dx=
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- int (1)/((1+e^(x))(1+e^(-x))) dx=
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- int (1)/(sqrt(e^(2x)-1))dx=
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- int e^(x" cosecx") [ (sin x - x cos x )/(sin^(2) x) ] dx =
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- int (tan^(9)x)/(sin x cosx) dx=
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- int(1//3)^(1)(x-x^(3))^(1//3)/(x^(4))dx=
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- int (1)/(x^(4) 4 sqrt(x^(4) + 1)) dx =
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- int (dx)/(x^(2) sqrt(4 - x^(2))) =
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- int (1)/(x^(2)sqrt(1+x^(2)))dx=
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- int (1)/((16 + x^(2))^(3//2)) dx =
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- int (1)/((x^(2)- 25)^(3//2)) dx =
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- int sin (tan^(-1) x) dx =
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- int (dx)/(x^(1//5)(1 +x^(4//5))^(1//2)) =
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- int (sin 2x)/(a cos^(2)x+b sin^(2)x)dx=
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- If ((x- 1)^(2))/((x^(2) +1)^(2)) dx = tan^(-1) x + g (x) + c then g (x...
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- int [(sqrt(x))/sqrt(a^(3)-x^(3))]dx=g(x)+c rArr g(x)=
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- int sqrt((cos x - cos^(3) x)/(1 -cos^(3) x)) dx =
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- int (3)/(2x^(2) - x- 1) dx =
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- If alpha gt 1 , then int (dx)/(x^(2) + 2 alpha x + 1) =
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