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int x cosec x Cotx dx =...

`int ` x cosec x Cotx dx =

A

xcosecx - log `| tan ""(x)/(2)| + c`

B

`-`xcosecx + log `| tan ""(x)/(2)| + c`

C

xcosecx - 2log `| tan ""(x)/(2)| + c`

D

xCotx + log `|tan ""(x)/(2)|+ c`

Text Solution

Verified by Experts

The correct Answer is:
B
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