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AAKASH SERIES-INDEFINITE INTEGRALS -EXERCISE -II
- int (("cosx")/(x) - "sinx.logx") dx =
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- int (1 + x -x^(-1)) e^(x + x^(-1)) dx =
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- int e^(-5x).cos 12 x dx =
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- int 3^(x) cos 5x dx =
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- Evaluate the integerals. int cos (log x) dx on (0,oo).
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- If I(n)= int(sin nx)/(cos x)dx, then I(n)=
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- If I(m.n) = int sin^(m) x cos^(n) xdx then I(5,4) =
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- If I(n) = int (e^(ex))/(x^(n)) " dx then " I(n) - (a)/(n-1) .I(n-1) =
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- If I(n) = int (log x)^(n) dx then I(6) + 6I(5) =
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- Statement-I: int (dx)/(sqrt(9 -x^(2))) = sin^(-1) ((x)/(3)) + c Statem...
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- S(1) : int (x^(5))/(x^(2) + 1) dx = (x^(4))/(4) - (x^(2))/(4) - (x^(2)...
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- If the curve f(x) = int e^(x) dx passing through (0,1) then the ascend...
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- If int (1)/(sqrt(x^(2) + x+ 1)) dx = a sinh^(-1) (bx + c ) + d then ...
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- If int (dx)/(cos^(3) x sqrt(2 sin 2x)) = (tan x)^(A) + C(tan x)^(B) + ...
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- Observe the following statements Assertion (A) : int((x^(2) -1)/(x^(...
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- Assertion (A) : int (2 x tan x sec^(2) x + tan^(2) x) dx = x tan^(2)...
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- The anti derivativ of f(x) = 1 +2^(x) log 2 is g(x) and the curve y =...
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- If int (1)/(cos^(6) x + sin^(6) x) dx = tan^(-1) f(x) + C then f(x) =
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- int(f(x)g'(x)-f'(x)g(x))/(f(x)g(x)) [ log (g(x))-log(f(x))]dx=
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- If int x^(3)e^(5x)dx-(e^(5x))/(5^(4))(f(x))+0(3) then f(x)=
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