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int sin 5x cos 3x dx=...

`int sin 5x cos 3x dx=`

A

`(1)/(2) [ (cos 2x)/(2) + (cos 8x)/(8) ] + C`

B

`(1)/(2) [ - (cos 2x)/(2) + (cos 8x)/(8) ] + C `

C

`(1)/(2) [ - (cos 2x)/(2) - (cos 8x)/(8) ] + C `

D

`(1)/(2) [ (cos 2x)/(2) - (cos 8x)/(8) ] + C `

Text Solution

Verified by Experts

The correct Answer is:
C
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