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int e^(cot x + 2" log cosecx") dx =...

`int e^(cot x + 2" log cosecx") ` dx =

A

`e^(cot x)` + c

B

`- e^(cotx ) + c`

C

`e^(cose x )+ c `

D

`- e^(cosec x) + c`

Text Solution

Verified by Experts

The correct Answer is:
B
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