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int (1)/(4 + 5 cos 2 theta) d theta =...

`int (1)/(4 + 5 cos 2 theta) d theta = `

A

`(1)/(6) log |(3 + tan theta)/(5 - tan theta)| + c `

B

`(1)/(3) log |(2 + tan theta)/(3- tan theta)| + c `

C

`(1)/(6) log |(3 + tan theta)/(3 - tan theta)| + c `

D

`(1)/(2) log |(3 + tan theta)/(3 - tan theta)| + c `

Text Solution

Verified by Experts

The correct Answer is:
C
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