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int cosx.log (tan""(x)/(2)) dx =...

`int ` cosx.log `(tan""(x)/(2)) ` dx =

A

sinx.logtanx- x + c

B

`-`sinx.log tan`(x)/(2)` + x + c

C

`-`sinx.log tan `(x)/(2)` - x + c

D

sinx.log tan `(x)/(2) ` - x + c

Text Solution

Verified by Experts

The correct Answer is:
D
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