int e^(sinx).sin2x dx =...

`int e^(sinx)`.sin2x dx =

A

`2e^("sinx")`(sinx + 1) + c

B

`e^("sinx")` (sinx +2) + c

C

`e^("sinx")` (2sinx - 2) + c

D

`e^("sinx")` (3 sinx - 2) +c

Text Solution

Verified by Experts

The correct Answer is:

C

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