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If I(n) = int ("cosnx")/("cosx") dx the...

If `I_(n) = int ("cosnx")/("cosx") ` dx then `I_(n)` =

A

`- (2)/((n- 1)) " cos (n - 1) x" + I_(n - 2) `

B

`(2)/((n- 1)) " cos (n - 1) x" + I_(n - 2) `

C

` (2)/((n- 1)) " sin (n - 1) x" - I_(n - 2) `

D

`- (2)/((n- 1)) " sin (n - 1) x" + I_(n - 2) `

Text Solution

Verified by Experts

The correct Answer is:
C
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