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AAKASH SERIES-DEFINITE INTEGRALS-EXERCISE - I
- If int(0)^(k)(1)/(2+8x^(2))dx=(pi)/(16) then k=
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- The value of I=int(0)^(pi//2)((sinx+cosx)^(2))/(sqrt(1+sin2x))dx is
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- int(0)^(pi)(1)/(1+sinx)dx=
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- int(0)^(pi//4)(Sin^(9)x)/(Cos^(11)x)dx=
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- int(0)^(1)sqrt((1-x)/(1+x))dx=
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- int(2)^(5) sqrt((x-2)/(5-x))dx=
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- int(2)^(3) (dx)/(sqrt((x-2)(3-x)))=
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- int(0)^(1)sqrt(x(1-x))dx=
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- int(0)^(pi//2)(1)/(4 cos^(2)x+9sin^(2)x)dx=
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- int(0)^(pi//4) (dx)/(2+sin^(2)x)=
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- int(0)^(pi//2) x sin x dx =
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- int(0)^(pi//2) e^(x) (cos x - sin x ) dx =
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- int(0)^(1)(xe^(x))/((x+1)^(2))dx=
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- int(0)^(1) x sin^(-1) x dx =
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- int(0)^(1)Tan^(-1)((2x)/(1-x^(2)))dx=
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- int(0)^(ln 2) Sin h 2x dx=
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- int(0)^(pi//2) (Sec x)/(Sec x + Cosec x) dx=
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- int(0)^(pi//2)(dx)/(1+tan^(3)x)=
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- int(0)^(pi//2)(200 sin x + 100 cos x)/(sin x + cos x) dx =
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- int(0)^(pi//2) (5 tan x - 3 cotx)/(tan x + cot x) dx=
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