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The solution of x(dy)/(dx) + 2y = x^(2) ...

The solution of `x(dy)/(dx) + 2y = x^(2) log x` is

A

`yx^(2) = (x^(4))/(4)log x - (x^(4))/(16) + c`

B

`yx^(2) = (x^(4))/(4)log x + (x^(4))/(16) + c`

C

`xy^(2) = (x^(4))/(4)log x - (x^(4))/(16) + c`

D

`xy^(2) = (x^(4))/(4)log x - (x^(4))/(6) + c`

Text Solution

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The correct Answer is:
A
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