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The solution of cos y log (sec x + tan x...

The solution of cos y log (sec x + tan x)dx = cos x log (sec y + tan y) dy is

A

`[log (sec x + Tan x)]^(2) - [log (sec y + Tany)^(2)] = c`

B

`[log (sec x + Tan x)]^(2) + [log (sec y + Tany)]^(2) = c`

C

`[log (sec x - Tan x)]^(2) - [log (sec y - Tany)]^(2) = c`

D

`[log (sec x - Tan x)]^(2) + [log (sec y + Tany)]^(2) = c`

Text Solution

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A
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AAKASH SERIES-DIFFERENTIAL EQUATIONS-Exercise - II
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