[" EXAMPLE "8quad " Let "cos(alpha+beta)=(4)/(5)" and let "sin(alpha-beta)=(5)/(13)," wh "],[0

cos(alpha-beta)=(3)/(5),sin(alpha+beta)=(5)/(13) then tan2 alpha

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13) , where 0 le alpha , beta=(pi)/(4) . Then tan2alpha=

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13), where 0<=alpha,beta<=(pi)/(4) Then tan2 alpha=(36)/(33) b.(19)/(12) c.(20)/(7)d*(25)/(16)

Let cos(alpha+beta)=(4)/(5) and let sin (alpha-beta)=(5)/(13) where 0<=alpha,beta<=(pi)/(4). Then tan2 alpha=(56)/(33)(b)(19)/(12)(c)(20)/(7) (d) (25)/(16)

If sin(alpha+beta)=(4)/(5), sin(alpha-beta)=(5)/(13) , find the value of tan 2alpha :

Let cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) where 0<=alpha,beta<=(pi)/(4) then find tan(2 alpha)