If stress-strain relation for volametric change is in the from `(DeltaV)/(V_(0))= KP` where P is applied uniform pressure, then K stands for

The dimensions of gamma in the relation v = sqrt((gamma p)/(rho)) (where v is velocity, p is pressure , rho is density)

For a constant hydraulic pressure on an object, the fractional change in the object's volume ((Delta V)/(V)) and its compressibility ((1)/(K)) are related as

An ideal gas ((C_(p))/(C_(v))=gamma) has initial volume V_(0) is kept in a vessel. It undergoes a change and follows the following relation P = kV^(2) (where P is pressure, and V is volume) find the change in internal energy of the gas if its final pressure is P_(0) :

An ideal gas ((C_(p))/(C_(v))=gamma) has initial volume V_(0) is kept in a vessel. It undergoes a change and follows the following relation P = kV^(2) (where P is pressure, and V is volume) find the change in internal energy of the gas if its final pressure is P_(0) :

Two soap bubble are combined isothermally to form a big bubble of radius R. If DeltaV is change in volume, DeltaS is change in surface area and P_(0) is atmospheric pressure then show that 3P_(0)(DeltaV)+4T(DeltaS)=0

Two soap bubble are combined isothermally to form a big bubble of radius R. If DeltaV is change in volume, DeltaS is change in surface area and P_(0) is atmospheric pressure then show that 3P_(0)(DeltaV)+4T(DeltaS)=0

A gas satisfies the relation pV^(5//3) = k , where p is pressure, V is volume and k is constant. The dimension of constant k are

The compressibility of a material is B.A cube of side 'a' is made with this material. If a uniform pressure P is applied on the cube from all the sides the fractional change in its length will be