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" 35."y=sqrt((1-cos2x)/(1+cos2x))" का अव...

" 35."y=sqrt((1-cos2x)/(1+cos2x))" का अवकलन "x" के सापेक्ष जात कीजिए । "

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If y sqrt((1-cos2x)/(1 + cos2x))" then " dy/dx = 0

inttan^-1sqrt((1-cos2x)/(1+cos2x))dx

Derivative of sqrt((1-cos2x)/(1+cos2x))

Differentate : sqrt((1-cos2x)/(1+cos2x))

Differentate : sqrt((1-cos2x)/(1+cos2x))

[(d)/(dx)[log sqrt((1-cos2x)/(1+cos2x))]

intcot^(-1)sqrt((1+cos2x)/(1-cos2x))dx is:

int tan^(-1)( sqrt((1-cos2x)/(1+cos2x)))dx