`(1+x^(2))(dy)/(dx)+y=tan^(-1)x` को हल कीजिए।

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(dy)/(dx)=1+x tan(y-x)

Solve: (1+x^2)(dy)/(dx) = y+tan^(-1)x

Solve the following differential equations (i) (1+x^(2)) (dy)/(dx) + y = e^(tan^(-1))x (ii) (1+x^(2))(dy)/(dx) + y = tan^(-1)x

y^(2)-(dy)/(dx)=x^(2)(dy)/(dx) A) y^(-1)+tan^(-1)x=c B) x^(-1)+tan^(-1)y=c C) y+tan^(-1)x=c D) x^(-1)+y^(-1)=tan^(-1)x+c

tan^(-1)((dy)/(dx))=x+y