A cell of itnernal resitance `1.5 Omega` and of e.m.f. `1.5` volt balances `500 cm` on a potentiomter wire. If a wirr of 15 `Omega` is connected between the balance point and the cell, then tha balance point will shift

A cell of internal resistance of 1 ohm and emf 5 volts balances on a potentiometer wire at length of 2 meter. The driving battery has emf of 50 volts. If the cell is shunted by 1 ohm resistance wire then find by what amount balance point will shift?

In an experiment to determine the internal resistance of a cell of emf 1.5 V, the balance point in the open cell condition is 76.3 cm. When a resistor of 9.5 ohm is used in the external circuit of the cell the balance point shifts to 64.8 cm of the potentiometer wire. Determine the internal resistance of the cell.

The e.m.f. of a cell is balanced by fall of potential along 281 cm of potentiometer wire. If a resistance of 8 Omega is connected across the cell , the balancing length is found to be 151 cm. Calculate internal resistance of a cell.

The balancing length on a potentiometer wire with a cell of emf 2V and internal resistance 1Omega connected in the secondary circuit with no load is 200cm . If a resistor of 19Omega is connected parallel to the cell, the balancing length